Default wizard button in ASP.NET

Jan

2009

Default wizard button in ASP.NET

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When you press enter/return on a wizard control in ASP.NET, the default action is to just submit the form, disregarding any buttons which were pressed. This seems pretty counter-intuitive to me – if I press enter on a form, it should be obvious I want to go ‘Next’. After two hours trying to debug an installer wondering why it seemed to work sometimes and not others I eventually tracked it down to the default button. I’m using a master page, but the principle is the same if you’re not.

The method I used uses the Page_Load event to set the default button for the form.

if(!Page.IsPostBack) { // First page, nothing clicked
    Master.Page.Form.DefaultButton = wzdInstall.FindControl("StartNavigationTemplateContainerID$StartNextButton").UniqueID;
} else {
    switch(wzdInstall.ActiveStepIndex) { // set the default button to next
        case 0: //page has posted back but is still on page one, about to load page 2
        default:
            Master.Page.Form.DefaultButton = wzdInstall.FindControl("StepNavigationTemplateContainerID$StepNextButton").UniqueID;
            break;
        case 1: // my wizard only had three steps, but this should be the number of steps-1
            Master.Page.Form.DefaultButton = wzdInstall.FindControl("FinishNavigationTemplateContainerID$FinishButton").UniqueID;
            break;
    }
}

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DRWebMonkey says:

March 11, 2009 at 5:09 pm

I used the following, inspired by your code from inside the ActiveStepChanged step

        If CType(sender, Wizard).FindControl("StepNavigationTemplateContainerID$StartNextButton") IsNot Nothing Then
            Page.Form.DefaultButton = CType(sender, Wizard).FindControl("StepNavigationTemplateContainerID$StartNextButton").UniqueID
        End If
        If CType(sender, Wizard).FindControl("FinishNavigationTemplateContainerID$FinishButton") IsNot Nothing Then
            Page.Form.DefaultButton = CType(sender, Wizard).FindControl("FinishNavigationTemplateContainerID$FinishButton").UniqueID
        End If

bahar says:

May 18, 2009 at 6:36 am

hi,

I get exception error when using this code in page load function of asp.net C#.
plz let me know what should I do?
my code is exactly:

*if (!Page.IsPostBack)
        { // First page, nothing clicked
            Master.Page.Form.DefaultButton = Wizard1.FindControl("StartNavigationTemplateContainerID$StartNextButton").UniqueID;
        }
        else
        {
            //Wizard1.ActiveStepIndex = 0;
            switch (Wizard1.ActiveStepIndex)
            { // set the default button to next
                case 0: //page has posted back but is still on page one, about to load page 2
                    break;
 
                case 2: // my wizard only had three steps, but this should be the number of steps-1
                    Master.Page.Form.DefaultButton = Wizard1.FindControl("FinishNavigationTemplateContainerID$FinishButton").UniqueID;
                    break;
 
                default:
                    Master.Page.Form.DefaultButton = Wizard1.FindControl("StepNavigationTemplateContainerID$StepNextButton").UniqueID;
                    break;
 
            }
        }

Echilon says:

May 18, 2009 at 7:45 am

And the exception is..?

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Default wizard button in ASP.NET

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