Comments on: Default wizard button in ASP.NET

By: Echilon

Echilon — Mon, 18 May 2009 07:45:23 +0000

And the exception is..?

By: bahar

bahar — Mon, 18 May 2009 06:36:40 +0000

hi,

I get exception error when using this code in page load function of asp.net C#.
plz let me know what should I do?
my code is exactly:

*if (!Page.IsPostBack)
        { // First page, nothing clicked
            Master.Page.Form.DefaultButton = Wizard1.FindControl("StartNavigationTemplateContainerID$StartNextButton").UniqueID;
        }
        else
        {
            //Wizard1.ActiveStepIndex = 0;
            switch (Wizard1.ActiveStepIndex)
            { // set the default button to next
                case 0: //page has posted back but is still on page one, about to load page 2
                    break;
 
                case 2: // my wizard only had three steps, but this should be the number of steps-1
                    Master.Page.Form.DefaultButton = Wizard1.FindControl("FinishNavigationTemplateContainerID$FinishButton").UniqueID;
                    break;
 
                default:
                    Master.Page.Form.DefaultButton = Wizard1.FindControl("StepNavigationTemplateContainerID$StepNextButton").UniqueID;
                    break;
 
            }
        }

By: DRWebMonkey

DRWebMonkey — Wed, 11 Mar 2009 17:09:27 +0000

I used the following, inspired by your code from inside the ActiveStepChanged step

        If CType(sender, Wizard).FindControl("StepNavigationTemplateContainerID$StartNextButton") IsNot Nothing Then
            Page.Form.DefaultButton = CType(sender, Wizard).FindControl("StepNavigationTemplateContainerID$StartNextButton").UniqueID
        End If
        If CType(sender, Wizard).FindControl("FinishNavigationTemplateContainerID$FinishButton") IsNot Nothing Then
            Page.Form.DefaultButton = CType(sender, Wizard).FindControl("FinishNavigationTemplateContainerID$FinishButton").UniqueID
        End If